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I stacked the frames in AstroStakkert3 and then fade them in After Effects, manually aligning the images over each other.

@@pibyte thanks! I once tried this too but mine came out very shaky.

You heard right!

Well, there are people in this world, that are too stupid to understand the difference between a shadow and a silhouette. And then there are people like you ...

@@pibyte He is a troll, no point in replying them.

Hey Jimbo, it's been over 4 months since you posted your comment. Just wondering if you've managed to find some 'smarts' from somewhere, or are you still an ignorant fool?

"because ISS is always bright" No it isn't.

@@pibyte I mean the visual lapse. (e.g. webpage spot the station information from your location).

​@@malchielrodriguez6718 It is really hard to tell from the comments if somebody is just pretending to be stupid or actually really does not get anything. When the Earth is between the Sun and the station there is no sunlight to reflect. It is black because it is a silhouette against the bright moon. Even my nephew understands this and he is 4.

@@pibyte you are not too smart are you. A full moon is when the Earth is between the Sun and the moon. And the moon is at its brightest. lol.

@@malchielrodriguez6718 When the station is in the earth's shadow, it's not going to be 'illuminated as a star' is it. Why have you not realised that in the footage, the ISS is passing through the earth's shadow?

I taught myself programming as a teenager - the Arduino is in fact very simple to program, there are many tutorials online that can help you out.

Ok Thanks!!!

ROTFL

Hello Tony. Sure, I put each frame on a seperate layer and then made a luminance mask out if it (increasing black and white contrast for a mask) and then use that to mask the station on every layer. On some frames I had to nudge the layer a little bit, because the seeing has moved the image (including the Moon surface in the bg) a little around.

@@pibyte Congratulation!! What software do you use to separate each frame for the final photo? thank you!

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Then explain how I watched a similar transit through my 8" telescope. Get out from behind your keyboard and go look through a telescope. Most areas have astronomy clubs that hold public observing sessions. I subscribe to receive emails that inform me when the ISS is making a pass over my location and the predictions are always spot on. Please explain how NASA manages to fake the passage of the ISS over my non-American home town, again and again and again.

Berndorf, Austria

You’re the fakest « human » being ever...

transit-finder.com/

I was about to write, there are sites that calculate everything for you and tell you where and when to go to watch it

You sure showed us how literat you are....

A toy that crosses all the sky over my head in less than 2 minutes... suuuuuuuuuure. Also this toy is flying all around the globe just in case someone dares to test this.... omg.

Hey David, I used a Barlow 2x lens to "double" the focus length. Good luck tonight ;)

Because ISS is MUCH closer, its orbit takes about 90 minutes, whereas the Moon takes almost 28 days to orbit Earth. When we see them together in conjunction, we see the apparent speed relative to each other in arc length (degrees, radians, etc) per unit of time (seconds, minutes, etc). The angular speed of both objects from a position on Earth is roughly: Moon 360º per 28 days = 0.00893º/minute ISS 360º per 90 minutes = 4º/minute

is the tesla car video passing the moon fake? its going way slower and should be further out in space too. thanks!

Why do you think the moon is faster than the ISS? Orbital speed of the moon is roughly 1 km/s while the ISS is traveling at 8 km/s. Also it is much closer to earth therefore appears even faster as David already showed.

@@99dlavall My calculations are, for an ISS orbit 400 km high: Orbital period: 92 minutes = 5500 seconds (roughly) Orbital length: (2*pi)*6800 = 43.000 km (roughly) ISS speed (declared): 27,600km/h = 7,7km/s (roughly) ISS angular speed (as calculated) = 360/5500 = 0,065 degrees/second Full Moon's angular dimension = roughly 1/2 degree My question is: if my calculations are right (and I'm not even sure, cause I'm not an astronomer, nor a flat-earther, just a simple mind at work), why is the transit happening so fast? It should have been roughly 8 seconds long. If anybody with more scientific knowledge could answer me, I'll surely be glad!

@@svenzikobombardo The quick answer, without calculating it, is that the field of view (from the Earth's surface, from which we observe both: ISS and Moon) of the arc length that ISS travels in one second is not 0.065, that would be the field of view if a person could observe it from the center of the earth. Being on the surface of Earth we are 94% closer to ISS then the center of Earth, which is the origin or center of radius for the 0.065 degrees/s. Does that answer it for you? If not, I'd be happy to calculate what the FOV is for an observer on the surface of the Earth, of the length of arc that ISS travels in one second. I assure you, it is much greater than 0.065 degrees. By the way, you can use transit-finder.com/ to acttually view ISS transits from a location near you.